quarta-feira, 25 de janeiro de 2012

Conjunto Sambossa - Isto e Bossa Nova Mesmo (1963)

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Originalmente postado no Loronix em 27 de fevereiro 2007.

Comentários originais incluídos.





When you start being confident that you know Bossa Nova, the artists, the groups, the trios and the most important records, here comes Caetano Rodrigues with this contribution in the middle of several other nice ones that we have been speaking about in the last days. Now I feel happy that my mess, explained in the last post, was of use, this is a nice Samba Jazz LP.


This is Conjunto Sambossa - Isto e Bossa Nova Mesmo (1963), for Pawal, featuring a not identified instrumental combo based on drums (played such like Milton Banana), bass, guitar, piano and a great brass session, everything arranged by Maestro Nelsinho. Isto e Bossa Nova Mesmo is that kind of record that makes you wonder who are the musicians in a first hearing. I will check for more information with Caetano Rodrigues tomorrow night, since we did not speak about Conjunto Sambossa already. I could not find any other Conjunto Sambossa LP searching the Internet.

Tracks include:

01 - Influência do Jazz (Carlos Lyra)
02 - Você e Eu (Carlos Lyra / Vinicius de Moraes)
03 - Barquinho (Roberto Menescal / Ronaldo Bôscoli)
04 - O Pato (Jaime Silva / Neusa Teixeira)
05 - Samba de Uma Nota Só (Tom Jobim / Newton Mendonça)
06 - Nós e o Mar (Roberto Menescal / Ronaldo Bôscoli)
07 - Ôba Lá Lá (João Gilberto)
08 - Só Danço Samba (Tom Jobim / Vinicius de Moraes)


3 Reply to "Conjunto Sambossa - Isto e Bossa Nova Mesmo (1963)"


JAmil on Tuesday, 27 February, 2007
Mais uma coisa fina demais
10 vezes escutando Influencia do Jazz e ainda não me dei por satisfeito.
Valews Zeca
Abraços
Jamil


zamurozien on Saturday, 10 March, 2007
There you are a handful of songs that anyone can miss. Let's check how this Conjunto Sambossa performs them; I am looking forward to being pleasingly surprised.
Obrigado, Caetano and zeca. Great tandem. :-D


Jéthero on Tuesday, 15 April, 2008
Onde está o link?


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